Probability: drawing two cards without replacement...?
a) 4/52 * 4/51 + 4/52 * 4/51 = 8 / 663
p(q,7) + p(7,q)
have consider 2 orders because original problem states 1 of each drawn, no order given.
b) should same answer part there equal numbers of each card.
if 2 cards drawn without replacement ordinary deck, find following probabilities:
a) queen , 7 drawn.
b) ace , 10 drawn.
(wouldn't these both same answer since there 4 each in deck?
Science & Mathematics Mathematics Next
Comments
Post a Comment