Probability: drawing two cards without replacement...?


a) 4/52 * 4/51 + 4/52 * 4/51 = 8 / 663

p(q,7) + p(7,q)

have consider 2 orders because original problem states 1 of each drawn, no order given.

b) should same answer part there equal numbers of each card.

if 2 cards drawn without replacement ordinary deck, find following probabilities:

a) queen , 7 drawn.
b) ace , 10 drawn.

(wouldn't these both same answer since there 4 each in deck?


Science & Mathematics Mathematics Next



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